try this:
lis. <- lapply(lis, function(x) if (length(ind <- grep("^IPI", x)))
x[ind[1]] else NULL)
lis.[!sapply(lis., is.null)]
I hope it helps.
Best,
Dimitris
----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven
Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
http://www.student.kuleuven.be/~m0390867/dimitris.htm
----- Original Message -----
From: "Johannes Graumann" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Thursday, February 22, 2007 3:33 PM
Subject: [R] List filtration
> Hello R-ologists,
>
> Imagine you have a list "list" like so:
>
>>list
> [[1]]
> [1] "IPI00776145.1" "IPI00776187.1"
>
> [[2]]
> [1] "Something" "IPI00807764.1" "IPI00807887.1"
>
> [[3]]
> [1] "IPI00807764.1"
>
> [[4]]
> [1] "Somethingelse"
>
> What I need to achieve is a filtered list "list2" like so:
>
>>list2
> [[1]]
> [1] "IPI00776145.1"
>
> [[2]]
> [1] "IPI00807764.1"
>
> [[3]]
> [1] "IPI00807764.1"
>
> So:
> - if sublist-entry 1 start with "^IPI" make it the list-entry.
> - otherwise chose the first "^IPI" sublist-entry present.
> - delete the list-entry if not "^IPI" sublist-entry present.
>
> Can anybody nudge me towards an elegant solution without looping - I
> have
> LOTS of entries to process ...
>
> Thanks for your Teachings,
>
> Joh
>
> ______________________________________________
> [email protected] mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
Disclaimer: http://www.kuleuven.be/cwis/email_disclaimer.htm
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