As indicated in ?boxplot it passes certain arguments to bxp so check out ?bxp where you will find various out... arguments:
boxplot(c(1:10, 20), outlty = 2, outcex = 0 ) On 3/27/07, AA <[EMAIL PROTECTED]> wrote: > Dear Users > > Is there any way to generate lines instead of points for outliers in the > boxplot > function? > Thanks > > AA. > [[alternative HTML version deleted]] > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
