In fact this implies that random-effects might not be the way to go for your data. When you're using random-effects the marginal covariance matrix is of the form:

V = Z D Z^t + Sigma,

where Z is the design matrix for the random-effects, D their covariance matrix and Sigma is the covariance matrix for the error terms. If the correlation between the repeated measurements of your sample units could be explain by a set of random-effects, then D should be a positive definite matrix. However, note that V might be positive definite even if D it is not, as in your case, which implies that the assumption of some common random-effects that the sample units share might not be valid.

Alternatively, you could model directly the marginal covariance matrix V using the 'correlation' and 'weights' arguments of gls().

I hope it helps.

Best,
Dimitris

----
Dimitris Rizopoulos
Ph.D. Student
Biostatistical Centre
School of Public Health
Catholic University of Leuven

Address: Kapucijnenvoer 35, Leuven, Belgium
Tel: +32/(0)16/336899
Fax: +32/(0)16/337015
Web: http://med.kuleuven.be/biostat/
    http://www.student.kuleuven.be/~m0390867/dimitris.htm



----- Original Message ----- From: "Tu Yu-Kang" <[EMAIL PROTECTED]>
To: <[email protected]>
Sent: Wednesday, April 11, 2007 12:34 PM
Subject: [R] negative variances


Dear R experts,

I had a question which may not be directly relevant to R but I will be
grateful if you can give me some advices.

I ran a two-level multilevel model for data with repeated measurements over time, i.e. level-1 the repeated measures and level-2 subjects. I could not get convergence using lme(), so I tried MLwiN, which eventually showed the
level-2 variances (random effects for the intercept and slope) were
negative values. I know this is known as Heywood cases in the structural equation modeling literature, but the only discussion on this problem in the literature of multilevel models and random effects models I can find is
in the book by Prescott and Brown.

Any suggestion on how to solve this problem will be highly appreciated.

Many thanks.

With best regards,

Yu-Kang




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