Another similar way to do this using apply is: apply(ar1==ar2,1,all)
Best, Finny Kuruvilla ***************************************************************** Finny Kuruvilla, MD, PhD Harvard Medical School Fellowship Program in Transfusion Medicine Broad Institute of MIT and Harvard Homepage: http://www.people.fas.harvard.edu/~kuruvill/home/ > Estimated people, > > I have two matrices: > > ar1 <- array(data=c(1:16),dim=c(4,4)) > ar2 <- array(data=c(1,2,3,3,5:16),dim=c(4,4)) > > They only differ in the fourth row. I would like to compare them in > order to know which columns are equal. > > The following works, but I would like to have a better solution, and > not > to use what someone called "prehistorical loops": > > for(i in c(1:4)) { cat(as.character(i),": ", > as.character(setequal(ar1[i,],ar2[i,])), "\n") } > 1 : TRUE > 2 : TRUE > 3 : TRUE > 4 : FALSE > > I cannot devise how to use the apply function for this. > Thanks a lot, > Federico ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
