You have the Chi^2 statistic and you know that it is on 1 degree of freedom with a 2-sample test. So
sdf <- survdiff(...) pchisq(sdf$chisq, df=1, lower=FALSE) might help in quite a common case. Generally you'll have to look at the printing function and make a modified copy to save the p-value: getAnywhere(print.survdiff) hth Petr Armin Goralczyk napsal(a): > Hi list,I want to use the p-value from the survdiff function > (packagesurvival) to reuse within a function in a Kaplan-Meier plot. > Thep-value is somehow not a component of the value list ?! > Thanks in advance-- A. GoralczykGöttingen, Ger. > [EMAIL PROTECTED] mailing > listhttps://stat.ethz.ch/mailman/listinfo/r-helpPLEASE do read the posting > guide http://www.R-project.org/posting-guide.htmland provide commented, > minimal, self-contained, reproducible code. > -- Petr Klasterecky Dept. of Probability and Statistics Charles University in Prague Czech Republic ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
