Hi, thanks for all suggestions - I found a solution myself within 5 minutes, but your suggestions are surely more elegant / shorter.
Thanks again, Hilmar hadley wickham schrieb: > Hi Hilmar, > > What was wrong with my solution? It's much simpler and shorter. > > cat <- sapply(df, is.factor) > df[cat] <- lapply(df[cat], factor) > > Hadley > > On 6/5/07, Hilmar Berger <[EMAIL PROTECTED]> wrote: > > -- Hilmar Berger Studienkoordinator Institut für medizinische Informatik, Statistik und Epidemiologie Universität Leipzig Härtelstr. 16-18 D-04107 Leipzig Tel. +49 341 97 16 101 Fax. +49 341 97 16 109 email: [EMAIL PROTECTED] ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
