Well, AFAIK, the definition of a p-value is the probability of observing something at least as extreme as the observed data.
If you observed z, and Z follows a std-normal p-value = P( Z < -abs(z) ) + P( Z > abs(z) ) = 2*P ( Z > abs(z) ) = 2*pnorm(z, lower.tail=FALSE) try z=0 (you should get 1) and z=1.96 (you should get 5%) b On Jun 11, 2007, at 11:34 AM, Carmen Meier wrote: > Benilton Carvalho schrieb: >> the recommendation was to use lower.tail=FALSE. >> >> b >> >> O > but then the results are significant and this does not match the > observation. > The results are matching the observations if the formula is > > pnorm(c > (1.8691945,0.5882351,2.4903091,1.9287802,2.3172983,2.2092593,2.2625959 > ,1.6395695), > lower.tail =TRUE) > > so I have any unknown problem .... anywhere :-( > > REgards Carmen ______________________________________________ [email protected] mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
