My mistake... last alternative should be:
c<-subset(c,regexpr("\\.1|\\.5|\\.6|\\.99999",rownames(c)) < 0)
--- Stephen Tucker <[EMAIL PROTECTED]> wrote:
> You can list them together using "|" (which stands for 'or'):
>
> c<-subset(c,!rownames(c) %in%
> grep(".1|.5|.6|.99999",rownames(c),value=T))
>
> but "." means any character for regular expressions, so if you meant a
> decimal place, you probably want to escape them with a "\\":
>
> c<-subset(c,!rownames(c) %in%
> grep("\\.1|\\.5|\\.6|\\.99999", rownames(c),value=T))
>
> Another option is
>
> c<-subset(c,regexpr("\\.1|\\.5|\\.6|\\.99999",c) < 0)
>
> because regexpr will return -1 for elements which do not contain a match.
>
>
> --- Ana Patricia Martins <[EMAIL PROTECTED]> wrote:
>
> > Hello R-users and developers,
> >
> > Once again, I'm asking for your help.
> >
> > There is other way to do the same more easily for applied simultaneous
> > grep???
> >
> > c<-subset(c,!rownames(c) %in% grep(".1",rownames(c),value=T))
> > c<-subset(c,!rownames(c) %in% grep(".5",rownames(c),value=T))
> > c<-subset(c,!rownames(c) %in% grep(".6",rownames(c),value=T))
> > c<-subset(c,!rownames(c) %in% grep(".99999",rownames(c),value=T))
> >
> > Thanks in advance for helping me.
> >
> > Atenciosamente,
> > Ana Patricia Martins
> > -------------------------------------------
> > Serviço Métodos Estatísticos
> > Departamento de Metodologia Estatística
> > INE - Portugal
> > Telef: 218 426 100 - Ext: 3210
> > E-mail: [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]>
> >
> >
> > [[alternative HTML version deleted]]
> >
> > > ______________________________________________
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> >
>
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