On 6/29/07, Birgit Lemcke <[EMAIL PROTECTED]> wrote:
>
> Hello Jim,
>
> thanks for your answer. At the moment I am using this code:
>
> Range0<-sapply(1:85, function(i) eval(parse(text=paste("range(V", i,
> ", na.rm=T)", sep=""))))
It is a matter of taste, but I tend to prefer:
a <- list()
for (i in 1:85) a[[i]] = get(paste("V", i, spe=""))
sapply(a, range, na.rm=T)
The first two lines put your variables inside a list (assuming they are not
already in one, e.g., in a data.frame).
This is especially interesting if you have other operations to perform on
the V1..V85 variables.
Christophe
and it works really fine.
>
> The code you sent me is also fine but how can I implement, that
> missing values are TRUE?
>
> Thanks a lot for your help
>
> Birgit
>
> Am 28.06.2007 um 13:01 schrieb Jim Lemon:
>
> > Birgit Lemcke wrote:
> >> Hello,
> >> (Power Book G4, Mac OS X, R 2.5.0)
> >> I would like to repeat the function range for 85 Vectors (V1-V85).
> >> I tried with this code:
> >> i<-0
> >> > repeat {
> >> + i<-i+1
> >> + if (i<85) next
> >> + range (Vi, na.rm = TRUE)
> >> + if (i==85) break
> >> + }
> >> I presume that the Vi is wrong, because in this syntax i is not
> >> known as a variable. But I don´t know how to say that it is a
> >> variable here.
> >> Would be nice if somebody could help me.
> >> Perhaps I´m thinking too complicated and there is an easier way to
> >> do this.
> > Hi Birgit,
> > This may be what you want:
> >
> > for(i in 1:85)
> > print(do.call("range",list(as.name(paste("V",i,sep="")))))
> >
> > Jim
> >
>
> Birgit Lemcke
> Institut für Systematische Botanik
> Zollikerstrasse 107
> CH-8008 Zürich
> Switzerland
> Ph: +41 (0)44 634 8351
> [EMAIL PROTECTED]
>
>
>
>
>
>
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>
>
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>
--
Christophe Pallier (http://www.pallier.org)
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