Hi, thank you very much for your reply. The function pgpd() is from the
package POT, and the 1.544 is the location parameter, 0.4477557 is the scale
parameter and -0.50113 is the shape parameter, which can be both negtive or
positive.


Vincent Goulet wrote:
> 
> Le 07-07-11 à 07:56, livia a écrit :
> 
>>
>> Hi, I would like to use the following codes to plot the CDF for pareto
>> distribution. Before doing this, I have plot the emperical one.
>>
>> x <- seq(1.6, 3, 0.1)
>> lines(x,pgpd(x, 1.544,0.4477557,-0.50113), col="red")
>>
>> Could anyone give me some advice whether the above codes are correct?
>>
>> Many thanks.
> 
> livia,
> 
> You seem to be struggling with the Pareto distribution... The above  
> code seems correct, but you do not say where you took the pdpd()  
> function from. This makes it harder for us to help you.
> 
> In you other message (https://stat.ethz.ch/pipermail/r-help/2007-July/ 
> 136137.html) you quote a negative scale parameter. The Pareto I know  
> has strictly positive shape and scale parameters.
> 
> Perhaps can you retry with functions ppareto() or pgenpareto() of  
> package actuar.
> 
> ---
>    Vincent Goulet, Associate Professor
>    École d'actuariat
>    Université Laval, Québec
>    [EMAIL PROTECTED]   http://vgoulet.act.ulaval.ca
> 
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
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> PLEASE do read the posting guide
> http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
> 
> 

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