The golden rule is that [[ ]] only returns one element: sapply(Lst, "[", 1, 1)
is probably what you want. On Sat, 14 Jul 2007, 'Forest Floor' aka 'rhago' aka 'Jeff' aka 'R User confused about his identity' wrote: > Hi, > > I would love an easy way to extract elements from a list. > > For example, if I want the first element from each of 10 arrays stored > in a list, > > Lst[[1:10]][1,1] seems like a logical approach, but gives this error: > "Error: recursive indexing failed at level 3" It doesn't if you really have a list of 2D arrays. > The following workaround is functional but can get annoying/confusing. > > first.element=vector() > for (i in 1:10){ first.element=c(first.element, Lst[[i]][1,1]) } > > Is there a better way to do this? Thanks for any help! > > Jeff > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. PLEASE DO! -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.