> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Nair,
> Murlidharan T
> Sent: Thursday, August 09, 2007 9:19 AM
> To: Moshe Olshansky; Rolf Turner; r-help@stat.math.ethz.ch
> Subject: Re: [R] small sample techniques
>
> Thanks, that discussion was helpful. Well, I have another question
> I am comparing two proportions for its deviation from the hypothesized
> difference of zero. My manually calculated z ratio is 1.94.
> But, when I calculate it using prop.test, it uses Pearson's
> chi-squared
> test and the X-squared value that it gives it 0.74. Is there
> a function
> in R where I can calculate the z ratio? Which is
>
>
> ('p1-'p2)-(p1-p2)
> Z= ----------------
> S
> ('p1-'p2)
>
> Where S is the standard error estimate of the difference between two
> independent proportions
>
> Dummy example
> This is how I use it
> prop.test(c(30,23),c(300,300))
>
>
> Cheers../Murli
>
>
Murli,
I think you need to recheck you computations. You can run a t-test on your
data in a variety of ways. Here is one:
> x<-c(rep(1,30),rep(0,270))
> y<-c(rep(1,23),rep(0,277))
> t.test(x,y)
Welch Two Sample t-test
data: x and y
t = 1.0062, df = 589.583, p-value = 0.3147
alternative hypothesis: true difference in means is not equal to 0
95 percent confidence interval:
-0.02221086 0.06887752
sample estimates:
mean of x mean of y
0.10000000 0.07666667
Hope this is helpful,
Dan
Daniel J. Nordlund
Research and Data Analysis
Washington State Department of Social and Health Services
Olympia, WA 98504-5204
______________________________________________
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
