One more question. After I collapse everything into one matrix, I would like to 
find the index of column that holds minimum value for each row. I remember that 
there is a function like maxCols but I can't seem to find the same thing for 
minimum value. Any suggestion please?

- adschai


 ----- Original Message -----From: Gabor Grothendieck Date: Sunday, August 19, 
2007 8:48 pmSubject: Re: [R] how to collapse a list of 1 column matrix to a 
matrix?To: "[EMAIL PROTECTED]" Cc: r-help@stat.math.ethz.ch> Try this:> > L <- 
list(`1` = matrix(1:4, 4), `2` = matrix(5:8, 4))> sapply(L, c)> > Note that the 
list component names are kept as column names in > the result> > > On 8/19/07, 
[EMAIL PROTECTED]  wrote:> > Hi,> >> > I encounter a situation where I have a 
list whose element is a > column matrix. Says,> >> > $'1'> > [,1]> > 1> > 2> > 
3> >> > $'2'> > [,1]> > 4> > 5> > 6> >> > Is there fast way to collapse the 
list into a matrix like a > cbind operation in this case? Meaning, the result 
should be a > matrix that looks like:> >> >      [,1]  [,2]> > [1,]    1      
4> > [2,]    2      5> > [3,]    3      6> >> > I can loop through all elements 
and do cbind manually. But I > think there must be a simpler way that I don't 
know. Thank you.> >> > - adschai> >> > __!
 ____________________________________________> > R-help@stat.math.ethz.ch 
mailing list> > https://stat.ethz.ch/mailman/listinfo/r-help> > PLEASE do read 
the posting guide http://www.R-> project.org/posting-guide.html> > and provide 
commented, minimal, self-contained, reproducible code.> >>

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