See ?window.zoo e.g. library(zoo)
# create test data tt <- c(-50, -49.996, -49.995, -49.96, -49.956, -49.955, -49.92, -49.916, -49.915, -49.88) z <- zoo(seq_along(tt), tt) window(z, c(-50, -49.96, -49.92, -49.88)) On 8/21/07, Todd Remund <[EMAIL PROTECTED]> wrote: > I have a zoo object for which I would like to subset using a vector of time > values. For example, I have the following time values represented in my zoo > object. > > -50.000 -49.996 -49.995 -49.960 -49.956 -49.955 -49.920 -49.916 -49.915 > -49.880 > > and would like to get observations corresponding to times > > -50 -49.96 -49.92 -49.88. > > What can I do without using the lapply or which functions? > > Thank you. > > Todd Remund > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
