On 8/21/07, Gonçalo Ferraz <[EMAIL PROTECTED]> wrote:
> Hi,
> Anyone knows what would be a short way of extracting a month from a date in
> numeric or integer format?
>
> months("1979-12-20")
> returns
> "December" in character format.
>
> How could I get 12 in numeric or integer format?
>
Here are a few solutions:
format(as.Date("1979-12-20"), "%m")
as.POSIXlt(as.Date("1979-12-20"))$mo + 1
as.numeric(substring("1979-12-20", 6, 7))
as.numeric(factor(months(as.Date("1979-12-20"), abbrev = TRUE), levels
= month.abb))
See R News 4/1 Help Desk article for more on dates.
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