Try: lapply(as.data.frame(t(DF)), function(x) unique(x[duplicated(x) & x > 0]))
On 8/23/07, dxc13 <[EMAIL PROTECTED]> wrote: > > Can anyone help me solve this problem...thanks! > > Consider a data frame, namely v, as such: > > v > X1 X2 X3 X4 X5 X1 X2 X3 X4 X5 > x1 1 2 -1 -1 -1 1 2 -1 -1 -1 > y1 1 2 -1 -1 -1 1 2 3 -1 -1 > > What I would like to do is to create an array or data frame with only the > elements that appear in the data frame more than once and are >= 0. > > I try this... > > v[v>=0] > [1] 1 1 2 2 1 1 2 2 3 > > which returns all >= 0 elements, but they are not in their respective rows > from the original data frame. I have tried using the duplicated() > function and can't seem to get it to work correctly. > > Essentially, the outcome I am trying to get is a df or array looking like: > > step 1...achieve this out of original df > [1] 1 2 1 2 > [2] 1 2 1 2 3 > > (the blank element in row 1, position 5 can be just be NA) > > step 2...take the above and get this...only the duplicated elements > [1] 1 2 > [2] 1 2 > > -- > View this message in context: > http://www.nabble.com/extracting-duplicated-elements-tf4318034.html#a12295213 > Sent from the R help mailing list archive at Nabble.com. > > ______________________________________________ > R-help@stat.math.ethz.ch mailing list > https://stat.ethz.ch/mailman/listinfo/r-help > PLEASE do read the posting guide http://www.R-project.org/posting-guide.html > and provide commented, minimal, self-contained, reproducible code. > ______________________________________________ R-help@stat.math.ethz.ch mailing list https://stat.ethz.ch/mailman/listinfo/r-help PLEASE do read the posting guide http://www.R-project.org/posting-guide.html and provide commented, minimal, self-contained, reproducible code.
