See ?regexpr to get the position; however, using sub we could remove
the dot and everything after it in one go. See ?regexp and ?sub .
Also there are some links to info on regular expressions in the Links
box on this page:
http://gsubfn.googlecode.com
> n <- regexpr(".", "apples.pears", fixed = TRUE)
> substr("apples.pear", 1, n-1)
[1] "apples"
> sub("[.].*", "", "apples.pears")
[1] "apples"
On 8/25/07, Mitchell Hoffman <[EMAIL PROTECTED]> wrote:
> This is a very simple question, so I apologize I couldn't find it online:
>
> I want to shorten the string 'apples.pears' to 'apples'.
>
> string='apples.pears'
> string1=substr(string,0,x)
>
> For x above, I would like to have a command like charAt(string,"."), i.e.
> the position of the period in the word, but I can't seem to find a charAt
> command in R.
>
> Thank you.
>
> [[alternative HTML version deleted]]
>
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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