Hello,
struggling with the very basic needs... :( any help appreciated.
#using the package doBY
#who drinks how much beer per day and therefor cannot calculate rowise
maxvals
evaluation=data.frame(date=c(1,2,3,4,5,6,7,8,9),
name=c("Michael","Steve","Bob",
"Michael","Steve","Bob","Michael","Steve","Bob"), vol=c(3,5,4,2,4,5,7,6,7))
evaluation #
maxval=summaryBy(vol ~ name,data=evaluation,FUN = function(x) { c(ma=max(x))
} )
maxval # over all days per person
#function
getMaxVal=function(x) { maxval$vol.ma[maxval$name==x] }
getMaxVal("Steve") # testing the function for one name is ok
#we want to add a column, that shows the daily drinkingvolume in relation to
the persons max-vol.
evaluation[,"relDrink"]= evaluation$vol/getMaxVal(evaluation$name)
#
# this brings the error:
#
#Warning message:
# Korrupter Data Frame: Spalten werden abgeschnitten oder mit NAs
# aufgefüllt in: format.data.frame(x, digits = digits, na.encode = FALSE)
errortest= evaluation$vol/getMaxVal(evaluation$name)
errortest
# this brings:
# numeric(0)
#target was the following:
#show in each line the daily consumed beer per person and in the next column
#the all time max consumed beer for this person´(or divided by daily vol):
#
# date name vol relDrink
#1 1 Michael 3 7
#2 2 Steve 5 6
#3 3 Bob 4 7
#4 4 Michael 2 7
#5 5 Steve 4 7
#6 6 Bob 5 7
#7 7 Michael 7 7
#8 8 Steve 6 6
#9 9 Bob 7 7
# who can help???
--
Das, was wir als freie Entscheidung erfahren, ist nichts als eine
nachträgliche Begründung von Zustandsveränderungen, die ohnehin erfolgt
wären.
Wolf Singer, Max-Planck-Institut für Gehirnforschung
[[alternative HTML version deleted]]
______________________________________________
R-help@stat.math.ethz.ch mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
