Dear Cory,
I am not familiar with SAS, but is this what you are looking for?
divisionTable <- matrix(c(1, "New England",
2, "Middle Atlantic",
3, "East North Central",
4, "West North Central",
5, "South Atlantic",
6, "East South Central",
7, "West South Central",
8, "Mountain",
9, "Pacific"),
ncol=2, byrow=T)
a <- NULL
a$divisionOld <- c(0,1,2,3,4,5)
a$divisionNew <-
as.character(factor(a$divisionOld,levels=divisionTable[,1],labels=divisionTable[,2]))
a$divisionNew
[1] NA "New England" "Middle Atlantic"
[4] "East North Central" "West North Central" "South Atlantic"
Kind regards,
Martin
Cory Nissen schrieb:
>
>
> Anybody?
>
>
> ________________________________
>
> From: Cory Nissen
> Sent: Tue 9/4/2007 9:30 AM
> To: r-help@stat.math.ethz.ch
> Subject: variable format
>
>
> Okay, I want to do something similar to SAS proc format.
>
> I usually do this...
>
> a <- NULL
> a$divisionOld <- c(1,2,3,4,5)
> divisionTable <- matrix(c(1, "New England",
> 2, "Middle Atlantic",
> 3, "East North Central",
> 4, "West North Central",
> 5, "South Atlantic"),
> ncol=2, byrow=T)
> a$divisionNew[match(a$divisionOld, divisionTable[,1])] <- divisionTable[,2]
>
> But how do I handle the case where...
> a$divisionOld <- c(0,1,2,3,4,5) #no format available for 0, this throws an
> error.
> OR
> divisionTable <- matrix(c(1, "New England",
> 2, "Middle Atlantic",
> 3, "East North Central",
> 4, "West North Central",
> 5, "South Atlantic",
> 6, "East South Central",
> 7, "West South Central",
> 8, "Mountain",
> 9, "Pacific"),
> ncol=2, byrow=T)
> There are extra formats available... this throws a warning.
>
> Thanks
>
> Cory
>
> [[alternative HTML version deleted]]
>
> ______________________________________________
> R-help@stat.math.ethz.ch mailing list
> https://stat.ethz.ch/mailman/listinfo/r-help
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> and provide commented, minimal, self-contained, reproducible code.
>
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