Hm, can't you compare the difference of the null and the residual deviances against a chi-square distribution with df=df_nulldev-df_resdev? (Just like when you use anova(model1, model2, test="Chi") during model simplification?) HTH, STG -- Stefan Th. Gries ----------------------------------------------- University of California, Santa Barbara http://www.linguistics.ucsb.edu/faculty/stgries -----------------------------------------------
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