Hello! I'm not sure if this appeared, so I thought I would try again. I am building a package on a RedHat supercomputer, using the gcc/gfortran and the accompanying mpi (MPICH) compilers. Here is the Makefile:
PKG_LIBS = $(LAPACK_LIBS) $(BLAS_LIBS) $(FLIBS) all: rmpigFortr.so tria.so rmpigFortr.so: mpifort -fPIC -c rmpigFortr.f90 -o rmpigFortr.o mpifort -shared rmpigFortr.o -o rmpigFortr.so tria.so: gfortran -m64 -fpic -O2 -g -pipe -Wall -Wp,-D_FORTIFY_SOURCE=2 -fexcep\ tions -fstack-protector-strong --param=ssp-buffer-size=4 -grecord-gcc-switches \ -m64 -mtune=generic -c tria.f90 -o tria.o gfortran -m64 -shared -L/usr/lib64/R/lib -Wl,-z,relro -o tria.so tria.o\ -L/usr/lib64/R/lib -lR Here is the NAMESPACE: # Generated by roxygen2: fake comment so roxygen2 overwrites silently. exportPattern("^[^\\.]") useDynLib(rmpigFortr) useDynLib(tria) When I build, check, and install the package, it seems to be fine. However, I have an R function that calls that "tria" Fortran subroutine. Here are the results: > library(rmpigFortr) > za <- tri(n=1000) Error in .Fortran("tria", as.single(y), as.integer(n)) : "tria" not resolved from current namespace (rmpigFortr) > But if I type in the call to .Fortran myself, it works. Any idea what I might be doing wrong, please? Thanks in advance, Sincerely, Erin -- Erin Hodgess Associate Professor Department of Mathematical and Statistics University of Houston - Downtown mailto: erinm.hodg...@gmail.com [[alternative HTML version deleted]] ______________________________________________ R-package-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-package-devel