Yes, it is possible, and always has been when I have checked (which is not a proof). You can check this by seeing that it has no negative eigenvalues in principal coordinates analysis (apart from occasional negative almost-zero). Legendre & Legendre book discuss this.
Cheers, Jari Oksanen > On 9 May 2019, at 10:21, Irene Adamo <i.adam...@gmail.com> wrote: > > Hi all, > > I have a very simple question: is it possible that the square-root of > Bray-Curtis values is Euclidean? if not, is there a way to transform > bray-curtis which is semi-quantitative in Euclidean? > > thanks a lot! > > [[alternative HTML version deleted]] > > _______________________________________________ > R-sig-ecology mailing list > R-sig-ecology@r-project.org > https://stat.ethz.ch/mailman/listinfo/r-sig-ecology _______________________________________________ R-sig-ecology mailing list R-sig-ecology@r-project.org https://stat.ethz.ch/mailman/listinfo/r-sig-ecology
