6 hours ago, Mark Carter wrote: > I would obtain the answer 3. Is there any way I can do this? The > following works, but I'm wondering if it's the best way: > (eval `(apply ,sym '(1 2))) > A more basic question would be: is there any way I can convert from > '+ to + - i.e. a symbol to a function?
Always good to read for such questions: http://docs.racket-lang.org/guide/eval.html -- ((lambda (x) (x x)) (lambda (x) (x x))) Eli Barzilay: http://barzilay.org/ Maze is Life! _________________________________________________ For list-related administrative tasks: http://lists.racket-lang.org/listinfo/users
