Well i gotÂ
(list(car'(())) ===> (()) (list(car'(3))) ===> (3) Are you saying I need to change (list(car ls)) ? ________________________________________ From: David Van Horn [dvanh...@ccs.neu.edu] Sent: Monday, September 17, 2012 3:37 PM To: Ashley Fowler Cc: Danny Yoo; users@racket-lang.org Subject: Re: [racket] Delete Second On 9/17/12 3:30 PM, Ashley Fowler wrote: > Disregard the last message with the questions, I get what your saying now. I > had to switch the sign. > > (define delete-second2 > (lambda(ls) > (if(> (length ls) 1) (append(list(car ls))(cdr(cdr ls))) > (list(car ls))))) > > Only problem I got now is the first test still doesn't work. >> (delete-second2 '()) ==> () >> (delete-second2 '(3)) ==> (3) There's a striking relationship between what comes in and what goes out in these two examples. What is that relationship? Do other examples of this length exhibit the same relationship? How is that relationship different from what (list (car ls)) computes? David ____________________ Racket Users list: http://lists.racket-lang.org/users