Well this is what I got so far...
(define deleteNth
(lambda(N LS)
(cond
(null? LS) LS)
((= N 0)(cdr LS))
(else(cons(car LS)(deleteNth(- N 1)(cdr LS))))))
and it keeps giving me the error of "cond: bad syntax (clause is not a
test-value pair) in: ls"
________________________________
From: Matthias Felleisen [matth...@ccs.neu.edu]
Sent: Monday, October 08, 2012 9:51 AM
To: Ashley Fowler
Cc: users@racket-lang.org
Subject: Re: [racket] Delete Nth Term
3 versions, all pass the test suite. Now write the function
pick-one-of-three : [List X X X] -> X
and turn in.
#lang racket
(require rackunit)
;; Nat [Listof X] -> [Listof X]
;; delete the n-th item from l, if there is one
(module+
test
(check-equal? (deleteNth 4 '()) '())
(check-equal? (deleteNth 0 '(a b c)) '(b c))
(check-equal? (deleteNth 3 '(a b c)) '(a b c))
(check-equal? (deleteNth 2 '(a b c)) '(a b)) )
(define (deleteNth n l)
(cond
[(= n 0) (rest l)]
[(< n (length l)) (append (take l n) (rest (drop l n)))]
[else l])
#;
(cond
[(empty? l) l]
[(zero? n) (rest l)]
[else (cons (first l) (deleteNth (sub1 n) (rest l)))])
#;
(cond
[(and (zero? n) (empty? l)) l]
[(and (positive? n) (empty? l)) l]
[(and (zero? n) (cons? l)) (rest l)]
[(and (positive? n) (cons? l)) (cons (first l) (deleteNth (sub1 n) (rest
l)))]))
On Oct 7, 2012, at 10:03 PM, Ashley Fowler wrote:
I need help with making a function that deletes the nth term from a list.(list
LS with its Nth element (with indexes starting at 0) deleted)
So far I have
(define (deleteNth N ls)
(if (null? ls)
ls
(deleteNth (- N 1) (cdr ls))))
The results should be ...
(deleteNth 4 '()) returns ()
(deleteNth 0 '(a b c)) returns (b c)
(deleteNth 3 '(a b c)) returns (a b c)
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