Yeah, my original version is 5.2.1. Now it works on the new version. Thanks, Eric! --Monic
On Fri, Nov 16, 2012 at 11:52 PM, Eric Dobson <[email protected]>wrote: > This example runs fine for me, but likely would not run fine on older > versions of racket (before submodules were released). > > I believe 5.3 added support for submodules and 5.3.1 was released recently. > > What version of racket are you running? Running (version) will tell you. > > > On Fri, Nov 16, 2012 at 10:43 PM, Monica Tomson > <[email protected]>wrote: > >> Hi, >> >> I want to use some quoted module name, and read this page in Racket >> documentation: >> http://docs.racket-lang.org/guide/Module_Syntax.html >> >> In the section 6.2.3, submodules, >> the code is: >> >> #lang racket <http://docs.racket-lang.org/reference/index.html> >> >> >> >> (module<http://docs.racket-lang.org/reference/module.html#(form._((quote._~23~25kernel)._module))> >> zoo racket >> >> >> (provide<http://docs.racket-lang.org/reference/require.html#(form._((lib._racket/private/base..rkt)._provide))> >> tiger) >> >> >> (define<http://docs.racket-lang.org/reference/define.html#(form._((lib._racket/private/base..rkt)._define))> >> tiger "Tony")) >> >> >> >> (require<http://docs.racket-lang.org/reference/require.html#(form._((lib._racket/private/base..rkt)._require))> >> 'zoo) >> >> >> >> tiger >> >> I put the above lines in to a fine and when press the run button, racket >> screams at me >> >> module: illegal use (not at top-level) in: (module zoo racket (provide >> tiger) (define tiger "Tony")) >> >> Am I missing something here? >> >> Thanks, >> -monica >> >> ____________________ >> Racket Users list: >> http://lists.racket-lang.org/users >> >> >
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