Thank you! I thought, that #'(1 . (2)) == #'(1 2) as '(1 . (2)) == '(1 2)
And Racket printer thinks same: > #'(1 . (2)) #<syntax:19:4 (1 2)> Fri, 15 Aug 2014 07:13:39 +0100 от Matthew Flatt <[email protected]>: >At Fri, 15 Aug 2014 09:55:11 +0400, Roman Klochkov wrote: >> What is the difference? >> >> > (let ([stx #'(1 (+ 3 4) 5 6)]) (equal? (syntax->list stx) (syntax-e stx))) >> #t Or syntax->list == (lambda (x) (let ([res (syntax-e x)]) (if (list? x) x >> #f))) ? > >You need a `.` to expose the difference: > > > (syntax-e #'(1 . (2))) > '(#<syntax::35 1> . #<syntax::39 (2)>) > > > (syntax->list #'(1 . (2))) > '(#<syntax::62 1> #<syntax::67 2>) > -- Roman Klochkov
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