I addition to my previous post:

If I understand well you are using posn-s.
A solution of the N-queens can be represented by a list or vector of lenhgth
N that for each row (or column) records the position of a queen in the
column (or row). This reduces the computation of time O(f(N^2)) to O(f(N)),
because only rows (or cullums) are considered, not all N^2 squares of the
board.
Jos 

-----Original Message-----
From: Brian Adkins [mailto:lojicdot...@gmail.com] 
Sent: sábado, 12 de marzo de 2016 23:33
To: Jos Koot
Cc: Racket Users
Subject: Re: [racket-users] Sequential vs. Parallel 13-Queens program

The code is a little difficult for me to read. It doesn't seem to collect
*all* solutions for a given N. If that's the case, would you be able to
modify it to do so to allow a more direct comparison?

> On Mar 12, 2016, at 1:19 PM, Jos Koot <jos.k...@gmail.com> wrote:
> 
> See https://en.wikipedia.org/wiki/Eight_queens_puzzle
> For a non recursive non-back-tracking algorithm.
> It is a loop that (when using a vector) can easily be unrolled in
parallelly
> executed loops.
> I implemented it as follows running on 2 processors:
> 
> #lang racket
> #|
> The following text is copied from article n queens of wikipedia:
> 
> This heuristic solves N queens for any N ≥ 4. It forms the list of
numbers
> for vertical positions (rows) of queens with horizontal position (column)
> simply increasing. N is 8 for eight queens puzzle.
> 
> 1. If the remainder from dividing N by 6 is not 2 or 3 then the list is
> simply all even numbers followed by all odd numbers ≤ N
> 2. Otherwise, write separate lists of even and odd numbers (i.e. 2,4,6,8 -
> 1,3,5,7)
> 3. If the remainder is 2, swap 1 and 3 in odd list and move 5 to the end
(i.
> e. 3,1,7,5)
> 4. If the remainder is 3, move 2 to the end of even list and 1,3 to the
end
> of odd list (i.e. 4,6,8,2 - 5,7,9,1,3)
> 5. Append odd list to the even list and place queens in the rows given by
> these numbers, from left to right (i.e. a2, b4, c6, d8, e3, f1, g7, h5)
> 
> In the following procedure I use a vector with as many elements as the
chess
> board has rows. Every element is assigned exactly once. Rows and columns
are
> counted from 0 (in the wikipedia article they are counted from 1)
> 
> Futures allow two or more loops to run simulanuously on two or more
> processors. If you don't have futures, replace (define f (future odd)) by
> (odd) and remove the touch.
> |#
> 
> (require racket/future)
> 
> (define (queens n)
> (define v (make-vector n))
> (define n-odd (quotient n 2))
> (define r (remainder n 6))
> (define (odd)
>  (case r
>   ((3)
>    (for ((k (in-range 0 (sub1 n-odd)))) (vector-set! v k (+ 3 (* 2 k))))
>    (vector-set! v (sub1 n-odd) 1))
>   (else
>    (for ((k (in-range 0 n-odd))) (vector-set! v k (add1 (* 2 k)))))))
> (define (even)
>  (case r
>   ((2)
>    (vector-set! v n-odd 2)
>    (vector-set! v (add1 n-odd) 0)
>    (for ((k (in-range (+ 2 n-odd) n)))
>     (vector-set! v k (+ 6 (* 2 (- k n-odd 2)))))
>    (vector-set! v (sub1 n) 4))
>   ((3)
>    (for ((k (in-range n-odd (- n 2))))
>     (vector-set! v k (+ 4 (* 2 (- k n-odd)))))
>    (vector-set! v (- n 2) 0)
>    (vector-set! v (- n 1) 2))
>   (else
>    (for ((k (in-range n-odd n)))
>     (vector-set! v k (* 2 (- k n-odd)))))))
> (define f (future odd))
> (even)
> (touch f)
> v)
> 
> (define (check v)
> (let ((n (vector-length v)))
>  (for/and ((x1 (in-range 0 n)))
>   (let ((y1 (vector-ref v x1)))
>    (for/and ((x2 (in-range (add1 x1) n)))
>     (let ((y2 (vector-ref v x2)))
>      (not
>       (or
>        (= y1 y2)
>        (= (abs (- x1 x2)) (abs (- y1 y2)))))))))))
> 
> (for/and ((n (in-range 4 100))) (check (queens n)))
> 
> (for ((k (in-range 2 9)))
> (printf "(expt 10 ~s) : " k)
> (let ((n (expt 10 k)))
>  (time (queens n))))
> 
> Runs fast:
> 
> (expt 10 2) : cpu time: 0 real time: 0 gc time: 0
> (expt 10 3) : cpu time: 0 real time: 0 gc time: 0
> (expt 10 4) : cpu time: 0 real time: 0 gc time: 0
> (expt 10 5) : cpu time: 0 real time: 0 gc time: 0
> (expt 10 6) : cpu time: 63 real time: 47 gc time: 32
> (expt 10 7) : cpu time: 203 real time: 140 gc time: 15
> (expt 10 8) : cpu time: 3183 real time: 2543 gc time: 1123
> 
> Times measured with DrRacket
> 
> Jos
> 
> 
> -----Original Message-----
> From: racket-users@googlegroups.com [mailto:racket-users@googlegroups.com]
> On Behalf Of Brian Adkins
> Sent: sábado, 12 de marzo de 2016 1:42
> To: Racket Users
> Subject: [racket-users] Sequential vs. Parallel 13-Queens program
> 
> I coded up a sequential and parallel version of N-Queens, then did a ton
of
> benchmark runs of 13-Queens to compare the time. For each configuration
> (sequential or parallel w/ M workers), I ran the programs 6 times, threw
out
> the high two & low two and averaged the middle two numbers.
> 
> The spreadsheet with timings is here:
> 
>
https://docs.google.com/spreadsheets/d/1LFwdZbBveaARY_AquGXY9jgaSJlOA03NQCV9
> TeYQ-l8/edit?usp=sharing
> 
> The code is here:
> 
> https://gist.github.com/lojic/aef0aec491d3dc9cb40b
> 
> I didn't spend any time refining/optimizing, so it's fairly crude, but
> informative nonetheless.
> 
> The executive summary of timings for the parallel version:
> 
> # Places      Time
> 1     34.9
> 2     19.7
> 3     13.8
> 4     12.3
> 5     11.9
> 6     12.9
> 7     12.1
> 8     12.2
> 
> The sequential version took 31.3 seconds.
> 
> The basic idea for the parallel version is to place the first 13 starting
> positions in a queue that the place workers will pull from and produce a
set
> of solutions with that starting position. Both the parallel and sequential
> versions collect all 73,712 solutions in a list and compute the length of
> it. I hardcoded the number of solutions as a quick & dirty way of
> determining completion in the parallel version just to allow me to get the
> timings easily.
> 
> It was great to finally write some Racket code that got all my cores
heated
> up :)
> 
> Brian
> 
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