> On Sep 25, 2017, at 5:52 AM, Matthias Felleisen <matth...@ccs.neu.edu> wrote:
>> On Sep 24, 2017, at 9:32 PM, 'John Clements' via users-redirect 
>> <us...@plt-scheme.org> wrote:
>> Now that I know how much faster ‘assert’ can be than ‘cast’, I’m eager to 
>> replace uses of ‘assert' all over the place.
>> Specifically, in my PL class, I’m hoping to get rid of uses of (cast … Sexp) 
>> that wind up principally in RHSes of match clauses.
>> In order to do this, I need a predicate of type (-> Any Boolean : Sexp). 
>> Well, strictly speaking, all I really need is the positive half, which I can 
>> construct like this:
>> (: sexp? (-> Any Boolean : #:+ Sexp))
>> (define (sexp? s)
>> (or (number? s)
>>     (symbol? s)
>>     (string? s)
>>     (and (pair? s) (sexp? (car s)) (sexp? (cdr s)))
>>     (null? s)))
>> This works fine, and I can use it in an assert. 
>> Should I just drop this on my students, or is there an existing s-expression 
>> checking predicate that I can use?
>> Apologies if I’m just not looking hard enough! 
> The definition of S-expression tends to be parameterized over the leafs 
> (atoms). I’d be surprised if your particular version existed. [I assume you 
> understand that you’re handing them a parser and that the use of this 
> predicate may slow down the function (in terms of O-class).] — Matthias

For this class, it’s all about ‘match’; last year, TR’s treatment of `match` 
wasn’t clever enough in many instances to deduce that a particular pattern 
variable’s value inhabits, say, Sexp, requiring either a cast or an assert. It 
may be that this year, TR is sufficiently sophisticated in its handling of 
`match` to obviate this need. If not, though, I’ll need either a cast or an 
assert. (If I’m thinking about this problem correctly, then *either* a cast or 
an assert is going to boost the asymptotic running time; even if TR can perform 
deduplication of casts to the same type, I think this still incurs the same 
asymptotic penalty.)



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