Looks like its for the same reason that (number->string -0) yields "0".
+nan.0 is special, but -nan.0 is the same as (- +nan.0) http://docs.racket-lang.org/reference/numbers.html On Mon, Feb 5, 2018 at 6:41 PM, David Storrs <david.sto...@gmail.com> wrote: > I noticed that (number->string -nan.0) yields "+nan.0" instead of "-nan.0" > as I would have expected. It's not an issue for me, but I was wondering why > this is? > > -- > You received this message because you are subscribed to the Google Groups > "Racket Users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to racket-users+unsubscr...@googlegroups.com. > For more options, visit https://groups.google.com/d/optout. -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@googlegroups.com. For more options, visit https://groups.google.com/d/optout.
