I have a short racket program/script that reads a file from the directory in
which it is stored. The directory structure is something like this:
a/
b/
c/
my-racket.rkt
my-data-file.txt
I want to be able to run the program from the command line no matter what is
the current working directory. E.G.:
a> racket b/c/my-racket.rkt
a/b> racket c/my-racket.rkt
a/b/c> racket my-racket.rkt
In order to do so, I need to provide the correct path to my-data-file.txt
depending on from where the script was launched. I haven’t learnt about Racket
modules yet so I resorted to searching Stack Overflow. I found a code snippet
that I used which worked:
(define script-dir (path-only (resolved-module-path-name
(variable-reference->resolved-module-path
(#%variable-reference)))))
Is this the best way to ascertain the directory of the “current module”?
Thanks in advance
Peter
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