In addition to the constructor, `foo` is also used for compile-time struct information. To avoid this, either supply #:name to designate a different identifier for compile-time struct type information, or declare #:omit-define-syntaxes to dismiss it.
Shu-hung On Thu, Jun 3, 2021 at 4:04 PM Sage Gerard <s...@sagegerard.com> wrote: > > My understanding is that you can shadow `foo`, but you cannot use `foo` in > any expression at the same scope where the struct's bindings appear. In this > context, some of `foo`'s lexical information is reserved so that `struct-out` > works correctly. > > On 6/3/21 5:01 PM, flirora wrote: > > > Am I correct in assuming that given a definition like > > (struct foo (x) #:constructor-name bar) > > I then can't define something named foo in the same module, even though > there's no constructor called foo? > > -- > You received this message because you are subscribed to the Google Groups > "Racket Users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to racket-users+unsubscr...@googlegroups.com. > To view this discussion on the web visit > https://groups.google.com/d/msgid/racket-users/02598ee4-4461-4815-bd4f-a8ac02c1118cn%40googlegroups.com. > > -- > ~slg > > -- > You received this message because you are subscribed to the Google Groups > "Racket Users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to racket-users+unsubscr...@googlegroups.com. > To view this discussion on the web visit > https://groups.google.com/d/msgid/racket-users/76c51dda-b80d-d74a-c691-d92fe11008e8%40sagegerard.com. -- You received this message because you are subscribed to the Google Groups "Racket Users" group. To unsubscribe from this group and stop receiving emails from it, send an email to racket-users+unsubscr...@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/racket-users/CAMTzy%2Bav%3Dh_muCMK9pH0FpmUvUU7t5rUFBk09a3zhT7DSAc_1g%40mail.gmail.com.
