El Viernes, 20 de Noviembre de 2009, Iñaki Baz Castillo escribió: > El Viernes, 20 de Noviembre de 2009, Григорий Фучеджи escribió: > > I think this would work > > (0x20 0x70..0xFF) | (0x21 0x00..0x8F) > > But I think there should be better solution > > ok, I'll try it. > Thanks.
Unfortunatelly I don't understand how to convert the following range: [#xF8-#x2FF] Could I convert it to?: [#x00F8-#x2FF] so then to Ragel grammar as?: (0x00 0xF8..0xFF) | (0x01 0x00..0xFF ) | (0x02 0x00..0xFF ) It seems too complex however... what about converting to binary? PS: But what is #x2FF? is it "0x2F 0xF0"? or "0x02 0xFF"? Thanks. -- Iñaki Baz Castillo <[email protected]> _______________________________________________ ragel-users mailing list [email protected] http://www.complang.org/mailman/listinfo/ragel-users
