Either you have to hack the string you've captured, like you did in this
solution, or you have to use a scanner. This parsing problem requires
delaying the action on the first '*' since you don't know if it is a
containing '*', or the first character in the terminating string.
On 11-09-16 11:12 AM, Henrique Pantarotto wrote:
Well, I solved this problem by using something like this:
action mark { text_start = fpc; }
action show { printf("'%.*s'\n", fpc - text_start - 1, text_start); }
main := '/*' >mark any* :>> '*/' @show;
I don't know if this is the "correct way" to solve this, but it worked. ;-)
Thanks
On Thu, Sep 15, 2011 at 6:37 PM, Henrique Pantarotto <[email protected]
<mailto:[email protected]>> wrote:
Hi, I've read the ragel manual a couple of times and searched the
mailing list and I couldn't find the solution to this problem. I
imagine the solution is there somewhere, but I couldn't find it
since I couldn't search the mailing list archive properly.
BTW, I don't really need to parse c comments, but I found this
example to match perfectly what I am trying to accomplish. I'm
really trying to parse and print data separated by a multi-character
token.
Page 29 of Ragel 6.7 manual shows an example on how to properly
parse C language comments, but the action @comm also parses the *
caracter at the ending "*/" as shown in the Graphviz image.
I tried many ways to solve this problem, but I couldn't do it. Can
someone help?
action comm { printf("%c", fc); }
p = "/* foo *** bar */";
I tried:
main := '/*' (any* -- '/*')@comm '*/';
main := '/*' any*@comm :>> '*/';
main := '/*' ( ( any @comm )* - ( any* '*/' any* ) ) '*/';
But it always prints: "foo *** bar *" (note the * at the end) and I
looking for a way for it to print just " foo *** bar ".
Is there an easy way to fix this?
Thanks in advance!
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