Unfortunately it doesn't quite work that straight forward when the
number of the different option groups = n =P


On Wed, Apr 1, 2009 at 12:52 AM, Mark Ratjens
<[email protected]> wrote:
>
> Hmm ... what idioms are we allowed then? :-)
>
> Iterate over the sizes
>    within each size
>       iterate over the colours
>          make a combination and stow it somewhere
>
> Does that make sense?
>
> Either that or get some sleep :-)
>
> Torm3nt wrote:
>> This may seem rather simple to some, but being late at night it's
>> driving me up the wall..
>>
>> The context behind this is I'm trying to create all unique product
>> options for a product.
>>
>> Consider:
>>
>> We have two product option groups, size and colour.
>>
>> Size contains: S, M, L, XL
>> Colour contains: red, blue, green, black, brown
>>
>> I need to write an algorithm (this isn't for ruby btw, so no ruby
>> idioms =P), that gets all unique combinations, for example:
>>
>> S red, S blue, S green, S black, S brown
>> M red, M blue.etc.etc.
>>
>> They're all valid, but I can't then go:
>>
>> red S - it's exactly the same option as before.
>>
>> I have tried to do this three different ways and each way I've hit a daed 
>> end.
>>
>>
>> HELP!
>>
>> =)
>>
>> >
>>
>>
>>
>
> >
>

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