Yes, whoever created that code in the first place did not include anything to 
test if a column is involved in >1 index in that table.  I don't think I've 
ever myself used a column as both an individual index and also involved as part 
of a multi-column index.

Karen

 

 

-----Original Message-----
From: 'Lawrence Lustig' via RBASE-L <[email protected]>
To: rbase-l <[email protected]>
Sent: Wed, Sep 28, 2016 9:30 am
Subject: Re: [RBASE-L] - How to drop a foreign key in a table using SQL



Okay, I took Karen's code and encapsulated it in a Stored Procedure so that I 
could automate this.  It only handles the simple case as discussed in my 
previous message (the column is used in only a single index and that index is 
the foreign key) but this will probably cover 90% of the cases.


To use, SET VAR vDeleted = (CALL DropForeignKey('MyTable', 'MyColumn')) and 
vDeleted will contain Y or N depending on whether it succeeded.


-------------------------------------------------------------------
-- DropForeignKey: Given a table and column names, drops the foreign
-- key on that column.  Returns 'Y' if successful, otherwise 'N'.
-- Will fail (return 'N') in complex cases
-- PUT DropForeignKey.PRC AS DropForeignKey pDFK_Table TEXT(18) pDFK_Column 
TEXT(18) RETURN TEXT(1)
-------------------------------------------------------------------


IF pDFK_Table IS NULL OR pDFK_Column IS NULL THEN
  GOTO Failed
ENDIF


SET VAR pDFK_TableID INT = NULL
SELECT SYS_TABLE_ID INTO pDFK_TableID vI FROM SYS_TABLES WHERE SYS_TABLE_NAME = 
.pDFK_Table
IF pDFK_TableID IS NULL THEN
  GOTO Failed
ENDIF


SET VAR pDFK_IndexName  TEXT = NULL
SET VAR pDFK_IndexCount INT = 0
SELECT MAX(SYS_INDEX_NAME), COUNT(*) INTO pDFK_IndexName, pDFK_Count +
  FROM SYS_INDEXES WHERE SYS_TABLE_ID = .pDFK_TableID AND SYS_COLUMN_NAME = 
.pDFK_Column +
  GROUP BY SYS_INDEX_NAME
IF pDFK_IndexName IS NULL OR pDFK_Count <> 1 THEN
  GOTO Failed
ENDIF


ALTER TABLE &pDFK_Table DROP CONSTRAINT &pDFK_IndexName


RETURN 'Y'


LABEL Failed
CLEAR VAR pDFK_%
RETURN 'N'

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