Damon, "IF" expressions in R:BASE cannot have sub-queries in them. You may need to SELECT into a variable before your test, or use the WHERE clause. Inspect the many R:BASE "functions" through the help contents, those that deal with date and time, and also notice that you automatically get the equivalent of a DATEDIFF expressed in days if you subtract one date from another.
Here's one way with the ADDYR() function: SELECT stuff FROM employee WHERE (ADDYR(dob,50)) <= .#DATE I don't recall when ADDYR() was added as a function, but if it's not in your version, you can use IYR(date), IYR4(date), IMON(date), or IDAY(date) to pull integer year, integer 4-digit year, integer month, or integer day of the month from any date value, or simply use the number of days calculation through date subtraction: SELECT stuff FROM employee WHERE ( (.#DATE - dob) >= (50 * 365.25) ) On Wed, Nov 5, 2008 at 5:27 PM, Gray, Damon <[EMAIL PROTECTED]> wrote: > I apologize for the flurry of questions today. As I said, I'm all of > "three days old" with RBase. I'm trying to do a SQL DATEDIFF, but don't > find that in RBase, so I'm getting today's date with .#DATE, and then > pulling a Date of Birth "DOB" from the EMPLOYEE table. I need to see if the > given employee is over 50 years old, so I'm not allowing for month, day and > year. I'm used to DATEDIFF taking care of that for me. How is this > calculated in RBase? Do I need to bust that DATE up into month, day and > year and do the math on each element of that datatype? > > > > IF (.#DATE - (SELECT DOB FROM EMPLOYEE) = 50) THEN > > -- Do stuff here > > ENDIF > > > > wwwww > > ( @ @ ) > > ------oOO---(_)---OOo------ > > Damon J. Gray > > Business System Services > > Anvil Corporation > > (360) 937-0770 > > oooo0 0oooo > > ( ) ( ) > > ---------\ (----) /---------- > > \__) (__/ > > >

