This is more of a solution to your problem than an answer to your question.
If the trailing space is not needed you can remove it/them with STRIM:
(STRIM(text))
Trims trailing blanks from text, returning a text string.
In the following example, the value of vstrim is the text string ABCDE
without the trailing blanks.
SET VAR vstrim = (STRIM('ABCDE '))
If the last char is a legitimate space, you could test the last
character of the string:
vLastChar = (SGET(TextString,1,(SLEN(TextString))))
Doug
On 12/10/2015 12:30 AM, md wrote:
Hello,
I need your help to know if the behavior of the function is
correct. If it is correct then I can use your help with a work around to
identifying a space as the last character of a string. Your help is greatly
appreciated.
I need to read the value entered by a user one character at a time so that
on each keystroke a search is perform on a table. Everything work well
unless the search involved more than one word. Function (SCLOC(String,' '))
does not work if the space is the last character of the String.
Examples:
String = 'RBASE Application'
(SCLOC(.String,' ')) = 6
String = 'RBase '
(SCLOC(.String,' ')) = 0
When a space is the last character of the string it is not recognized by
SLOC, SLOCP, or SLOCI. I am not sure if this is the correct behavior of
these functions. Any Blues Clues?
I am using:
R:BASE eXtreme 9.5 (32), U.S. Version, Build: 9.5.5.21111
Thank you,
Manuel de Aguiar V
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