Re: IFEQ question

[Bill Downall]

Dave,

I think the innermost expression gets evaluated first.  

Instead of this:

(IFEQ(t2.numclient, 0 , 0 ,(t2.unit / t2.numclient)))

See if this works better:

(t2.unit / (IFEQ(t2.numclient,0,1,t2.numclient))

Bill



On Sun, 5 Aug 2001 15:32:08 -0400, David Ebert wrote:

>The IFEQ statement, if I understand it correctly, is supposed to 
exclude the
>zero records (arg 4) because the numclient value (arg1) is not equal 
to zero
>(arg2).
>