I am faced with a date problem that was not in the intial design.  The date
was going to be defaulted to the conversion date but the value in the row
will now have to be converted in 94,000 rows of data of which there are nine
columns with date values which is being passed as eight characters
(YYYYMMDD).
I have created a routine that will be used to parse and convert the date
prior to writing the record.  (Not all records will be converted and not in
their original format - they are being made into load transactions for
SQLOADER).

I have tested this application and it works but I am concerned about time.
Can anyone see a faster way?
----------------------------------------------------------------------------
-----
-- Program: DCONV.RMD
-- Purpose: Receives an eight character representation of a date (YYYYMMDD)
and formats it to a date variable +
--                      for loading into an Oracle date format (YYYY-MM-DD)
-- RBase Date Setting is: MMDDYYYY

clear all variables

-- This variable will be passed from the calling program
set var vin_date text = '99999999'

-- Parse the 8 position text value for date
SET VAR vyr = (SGET(.vin_date,4,1))
SET VAR vmos = (SGET(.vin_date,2,5))
SET VAR vday = (SGET(.vin_date,2,7))

if vmos = '99' then
   set var vmos = '12'
endif
if vday = '99' then
   set var vday = '31'
endif

set var vnewdate2  = (RDATE (INT(.vmos),INT(.vday),INT(.vyr)))

clear all variables except vnewdate2
-- This will be passed back to the calling program
write .vnewdate2

return

Phil
[EMAIL PROTECTED]

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