What a great compliment to Larry... and so true. 

-----Original Message-----
From: William Carson <[EMAIL PROTECTED]>
To: [EMAIL PROTECTED] <[EMAIL PROTECTED]>
Date: Thursday, May 09, 2002 1:55 PM
Subject: RE: SQL Question


>I think the L in SQL stands for Larry.
>
>The statement works great!
>
>Thanks,
>Bill
>
>-----Original Message-----
>From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
>On Behalf Of William Carson
>Sent: Thursday, May 09, 2002 8:43 AM
>To: [EMAIL PROTECTED]
>Subject: RE: SQL Question
>
>I will try this one today and let you know how it works.
>
>Bill
>-----Original Message-----
>From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED]]
>On Behalf Of Lawrence Lustig
>Sent: Wednesday, May 08, 2002 9:32 PM
>To: [EMAIL PROTECTED]
>Subject: Re: SQL Question
>
><<
>I am looking for an SQL statement that will return the list of
>departments
>that is goes through and the order in which it goes through them.  In
>other
>words, I want:
>            Part                  Dept
>            ABC                 1
>            ABC                 2
>            ABC                 1
>            ABC                 15
>
>Does anyone have any suggestions?  Even if it takes more than one SQL
>statement or view.
>>>
>
>It only takes one.  This assumes that Seq is an Integer column:
>
>SELECT Part, Dept FROM Routing R1 WHERE NOT EXISTS +
>(SELECT * FROM Routing R2 WHERE R2.Part = R1.Part AND R2.Dept = R1.Dept
>AND
>R2.Seq = (R1.Seq-1))
>
>I tried it on your data, and it produced the results you want.  In
>brief, it
>selects only those rows for which the immediately preceding sequence
>number
>does not have the same part and dept values.
>--
>Larry
>
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