Le 15/11/12 15:14, Hadley Wickham a écrit :
On Thu, Nov 15, 2012 at 8:11 AM, Romain Francois
<rom...@r-enthusiasts.com> wrote:
I'm not getting the same results, so I might not make the same conclusions:
Unit: microseconds
expr min lq median uq max
1 sum(x) 16.072 16.161 16.2090 16.3110 21.721
2 sum1(x) 10.771 10.954 11.0445 11.1910 16.163
3 sum2(x) 48.438 48.567 48.6650 48.8425 61.116
4 sum2a(x) 10.806 10.965 11.0695 11.2080 17.401
5 sum3(x) 10.835 10.967 11.0490 11.1875 23.943
6 sum4(x) 10.847 10.989 11.0690 11.2160 16.331
For me that makes more sense.
I just discovered the problem with my accumulate. I was doing:
double total = std::accumulate(x.begin(), x.end(), 0);
instead of
double total = std::accumulate(x.begin(), x.end(), 0.0);
Hadley
Ah. Interesting. That makes sense, lots of conversion from double to int
to accumulate into an int.
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