Dear list members, I would like to be able to get an element pushed with its attributes, and I came across the following problem:
cppFunction(' std::vector<List> temp(List x){ std::vector<List> lower; lower.push_back(x); return(lower) ; } ') x = list(structure(1L, animal = "cat")) temp(x) temp(x[1]) temp(x[[1]]) # is there a way to not make this output without attributes? If I use RObject, it will solve it, but then I would later not be able to iterate over the object, because I can't seem to get the .size() of an RObject. Here is the code with the RObject: cppFunction(' std::vector<RObject> temp2(RObject x){ std::vector<RObject> lower; lower.push_back(x); return(lower) ; } ') x = list(structure(1L, animal = "cat")) temp2(x) temp2(x[1]) temp2(x[[1]]) # Now it works as I want, but the following wouldn't work: cppFunction(' std::vector<RObject> temp2_fail(RObject x){ std::vector<RObject> lower; int n x.size(); lower.push_back(x); return(lower) ; } ') Any ideas? ----------------Contact Details:------------------------------------------------------- Contact me: tal.gal...@gmail.com | Read me: www.talgalili.com (Hebrew) | www.biostatistics.co.il (Hebrew) | www.r-statistics.com (English) ----------------------------------------------------------------------------------------------
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