torsion bar diameter and scale are not linearly related. maximum shear stress due to torsion = (applied torque*maximum radius of bar) / polar area moment of inertia of the cross section
polar area moment of inertia for a circular cross section = (pi * diameter^4) / 32 maximum shear stress due to torsion should be less than (0.577 * the yield strength of the material) if you want the torsion bar to work without taking a set the angular deflection (in radians) due to the applied torque = (applied torque * length of bar) / (polar area moment of inertia of the cross section * shear modulus) On Wed, Oct 27, 2010 at 2:46 PM, neroc <[email protected]> wrote: > I`ve started my new tank , I`ve now got a basic hull and and gosh its > big ,Im out at scrap yards looking for steel tomorrow , im wondering > what diameter bar my tension axle will need to be , is it a case of > double the scale = double the diameter ? > im aiming for 1 inch mild steel rod, but I`ll have to see what I can > find. if anyone thinks other wise please let me know . > And if anyone knows of any 8No 10 inch wheels going give me a nod. > > Neil R > > -- > You are currently subscribed to the "R/C Tank Combat" group. > To post a message, send email to [email protected] > To unsubscribe, send email to [email protected] > Visit the group at http://groups.google.com/group/rctankcombat > -- You are currently subscribed to the "R/C Tank Combat" group. To post a message, send email to [email protected] To unsubscribe, send email to [email protected] Visit the group at http://groups.google.com/group/rctankcombat
