Hi there,
I am trying to play with rdflib and a (my) user defined vocabulary (name:
ODE).
To do that I have generated a class namespace/_ODE.py derived from
DefinedNamespace:
1 from rdflib.term import URIRef
2 from rdflib.namespace import DefinedNamespace, Namespace
3
4
5 class ODE(DefinedNamespace):
6 """
7 DESCRIPTION_EDIT_ME_!
8
9 Generated from: SOURCE_RDF_FILE_EDIT_ME_!
10 Date: 2022-05-02 08:38:55.619901
11 """
12
13 _fail = True
14
15 Function: URIRef
16 Equation: URIRef
17 hasDerivative: URIRef
18 Polynomial: URIRef
19 Ode: URIRef
20
21 _NS = Namespace("ode#")
22
As all the new "classes" of the ODE vocabulary are a specialization of the
class "Seq" I have created the module rdflib/ode.py:
1 from rdflib import Seq
2 from rdflib.namespace import RDF,ODE,MATH
3
4 __all__ = ["Function", "Equation","Polynomial","Ode"]
5
6
7 class Ode(Seq):
8 def __init__(self, graph, uri, seq=[], rtype="Ode"):
9 """Creates a Container
10
11 :param graph: a Graph instance
12 :param uri: URI or Blank Node of the Container
13 :param seq: the elements of the Container
14 :param rtype: the type of Container, one of "Bag", "Seq" or
"Alt"
15 """
16
17 self.graph = graph
18 self.uri = uri or BNode()
19 self._len = 0
20 self._rtype = rtype # rdf:Bag or rdf:Seq or rdf:Alt
21
22 self.append_multiple(seq)
23
24 # adding triple corresponding to container type
25 self.graph.add((self.uri, RDF.type, ODE[self._rtype]))
26
27 class Function(Ode):
28 def __init__(self, graph, uri, seq=[]):
29 Ode.__init__(self, graph, uri, seq, "Function")
30
31
32 class Equation(Ode):
33 def __init__(self, graph, uri, seq=[]):
34 Ode.__init__(self, graph, uri, seq, "Equation")
35
36 class Polynomial(Ode):
37 def __init__(self, graph, uri, seq=[]):
38 Ode.__init__(self, graph, uri, seq, "Polynomial")
With these two classes I can generate a RDF file in a declarative way.
For example we can create the Function c(t):
1 from rdflib import Graph, URIRef, RDF, BNode, RDFS, Literal, Seq, Bag,
Function, Equation, Times, Minus, Polynomial, Ode
2 from rdflib.namespace import ODE, MATH
3
4 # the time t
5 t = BNode("t")
6 graph.add((t,RDFS.label,Literal("t")))
7
8 c_of_t_label = BNode("c")
9 graph.add((c_of_t_label,RDFS.label,Literal("c")))
10 c_of_t_bn = BNode("c_of_t")
11
12 Function(graph,c_of_t_bn,[c_of_t_label,t])
And we obtain the following RDF:
_:c rdfs:label "c" .
_:t rdfs:label "t" .
_:c_of_t a ode:Function ;
rdf:_1 _:c ;
rdf:_2 _:t .
So far, so good. Now I want to execute a SPARQL query on this rdf to
retrieve the function.
1 import rdflib
2
3 from rdflib import Graph, URIRef, RDF, BNode, RDFS, Literal, Seq, Bag,
Function, Equation, Times, Minus, Polynomial, Ode
4 from rdflib.namespace import ODE, MATH
5
6 def main():
7 g = rdflib.Graph()
8 g.parse("ode_spe", format="ttl")
9
10
11 function = ODE.Function
12
13 query_test= "SELECT ?e WHERE {?e rdf:type ode:Function . }"
14 qres = g.query(query_test)
15
16 print (len(qres))
17 if __name__ == "__main__":
18 main()
But I have no results.
I probably do not do the right thing with ode:Function.
I have two questions:
- Is it the right way to add a user defined vocabulary ?
- And what can I do to retrieve the function with a SPARQL query
Thank for your help.
Olivier
--
http://github.com/RDFLib
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