I said: > > (. expr) > > is exactly equal to: > > expr
Alan Manuel Gloria: > This is necessary for Scheme rest arguments in definitions: > > define foo(. rest) > rest Just to be clear, I was meaning an UNprefixed (. expr). The idea is that: (. expr) is exactly equal to: expr Obviously we need to handle Scheme rest arguments, but those are prefixed. IE: foo(. rest) is equal to: (foo . rest) And I think that follows simply from the usual rule that f(...) is equal to (f ...). I'll go clarify the [Solution] page. --- David A. Wheeler ------------------------------------------------------------------------------ Live Security Virtual Conference Exclusive live event will cover all the ways today's security and threat landscape has changed and how IT managers can respond. Discussions will include endpoint security, mobile security and the latest in malware threats. http://www.accelacomm.com/jaw/sfrnl04242012/114/50122263/ _______________________________________________ Readable-discuss mailing list Readable-discuss@lists.sourceforge.net https://lists.sourceforge.net/lists/listinfo/readable-discuss
