this helps awesomely!
except - how do i replace in place the original strinput? do i keep a
position counter? do you have a simple example of that, and then i
promise i won't bother anybody.
i tried it with a counter, and i'm failing:
strinput = rm.replace(replacementpattern, positioncounter)
and everything gets offset in weird ways.
:(
-vv
On Feb 26, 2006, at 2:52 AM, dda wrote:
Do it in a loop:
Dim rm As RegexMatch
rm=r.search(strinput)
while rm<>Nil
<do whatever you have to do>
rm=r.search(strinput,rm.SubExpressionStartB(0)+LenB
(rm.SubExpressionString(0)))
wend
HTH
--
dda
libcurl4RB, [S]FTP transfers made easy
http://sungnyemun.org/?q=node/8
RBDeveloper Columnist, "Beyond the Limits"
http://rbdeveloper.com
On 2/26/06, vvor <[EMAIL PROTECTED]> wrote:
thank you, this works. but what if i need access to $1, $2, etc.,
outside of the r.replace? i'd like to process the replacement pattern
a bit based on conditions prior to the replacement. this is done with
regexmatch, yes? but that only matches once?
iow, i want to remember if i match a certain thing so i can alert
other code so that i can influence my replacement patterns a bit.
sorry if i'm dense.
-vv
_______________________________________________
Unsubscribe or switch delivery mode:
<http://www.realsoftware.com/support/listmanager/>
Search the archives of this list here:
<http://support.realsoftware.com/listarchives/lists.html>
_______________________________________________
Unsubscribe or switch delivery mode:
<http://www.realsoftware.com/support/listmanager/>
Search the archives of this list here:
<http://support.realsoftware.com/listarchives/lists.html>
