RB does have Xor and Xand. Look at the Bitwise class.
Tom Benson wrote:
Hello -
I came across some code for visual basic that I wanted to try to
port to
Rb for my personal use, however there are a few lines that go beyond
my knowledge
of what they do and why also how to make it work in Rb.
Here are the lines. Could some help me with this ?
Text2.Text = (Mid(Text1.Text, 1, 4) - &H69) Xor &H69 // HUH??? Rb
doesn't like this. I get the mid( ) but not the rest
The values that start with & are hex values. Your problem is most
likely the Xor boolean logic keyword, which I don't believe RB supports.
XOR is short for Exclusive Or. It is a value matching operand, rather
than a value comparator if that makes sense.
basically
XOR (different = true, same = false)
Therefore:
XOR works like AND, except where both values are false, eg;
value 1 = false
value2 = false
if value1 AND value2 then result = false (one or both values are false)
if value1 XOR value2 then return = true (both values are the same)
You may need to implement your own XOR function as follows:
Function XOR(v1 as boolean, v2 as boolean) as boolean
return v1 = v2
End Function
and
Text2.Text = Format(Hex(Text2.Text), "00") // Rb doesn't like this
either.
This is a simple matter of RB not being able to format string values
(Hex returns a string value). And since RB's Hex function seems to
return a 2 character Hex value for the passed string anyway (which is
what this formatter statement appears to do), this line is probably
not needed.
Thanks
Eric
NW,
Tom
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