On Apr 2, 2006, at 9:43 PM, Thomas Cunningham wrote:
I'm trying to get the same functionality of these C++ routines in Rb.
//#define SET_BIT(word,bit_flag) ((word)=((word) | (bit_flag)))
For this I have
word = Bitwise.BitOr(word, bit_flag)
Correct?
//#define RESET_BIT(word,bit_flag) ((word)=((word) & (~bit_flag)))
For this I see no equivalent in Rb for the ~ (tilda) operator which
produces
an integer with all of the bits set to 1, except the bit that
originally was
set to 1, that bit becomes a 0.
bitwise.BitXor(bit_flag , &b11111111)
mike
--
Mike Woodworth
[EMAIL PROTECTED]
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