Jason,
Thanks, added the constructor call, no change, so I am still missing
something here.
This is my button code (some lifted from the LR and dropped into the
button, commented out from experiments):
Thanks again!
Gary
Sub Action
Dim form as Dictionary
Dim TCPSocket1 as HTTPSecureSocket // is this my "subclass" ???
Dim req As String
Dim usr As String
Dim upw As String
Dim typ As String
TCPSocket1.constructor
// TCPSocket1.Secure=True
usr = "test"
upw = "pass"
typ = "application/x-www-form-urlencoded"
req = "Function=Auth&Source=EDI&Username=" + usr + "&Password=" +
upw + "&UploaderName=[MyApp]&UploaderVersion=5.0.1"
// create and populate the form object
// form = New Dictionary
// form.value("firstname") = "Bob"
// form.value("lastname") = "Brown"
// setup the socket to POST the form
// socket1.setFormData form
// TCPSocket1.SetPostContent (req, typ)
// TCPSocket1.post "https://www.somewebsite.com/form.php";
End Sub
On Apr 12, 2006, at 7:08 AM, Jason Essington wrote:
yup, it does work in 5.5.3
be sure that your subclass calls super.constructor in its constructor.
-jason
On Apr 11, 2006, at 10:03 PM, M Pulis wrote:
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